So for that you have choices, OpenVZ [0], cgroups [1], LXC [2], VServer [3], and KVM [4], the last of which is really a bunch of choices. [0] https://en.wikipedia.org/wiki/OpenVZ#Resource_management [1] https://en.wikipedia.org/wiki/Cgroups [2] https://en.wikipedia.org/wiki/LXC [3] https://en.wikipedia.org/wiki/Linux-VServer [4] http://www.linux-kvm.org/page/Management_Tools On Fri, Dec 16, 2016 at 2:33 PM, Steve Volumetric <volumetricsteve@gmail.com> wrote:
Yes, I should have used that phrasing in my question, and I see all that (I've already emailed myself a few of the links you provided) thanks for those anyway.
My concern/question is more...can I get crux to do that to itself on startup...or really, maybe a better way of describing what I would like to do is have 4 of my 6 cores untouched by whatever automatically schedules jobs so I (and only I) can manually set affinity to jobs on those free cores as I choose.
On Fri, Dec 16, 2016 at 5:30 PM, Louis Santillan <lpsantil@gmail.com> wrote:
The word you're looking for is CPU Affinity. See [0][1][2][3].
[0] https://sourceforge.net/projects/schedutils/ [1] https://www.cyberciti.biz/tips/setting-processor-affinity-certain-task-or-pr... [2] http://www.glennklockwood.com/hpc-howtos/process-affinity.html [3] http://man7.org/linux/man-pages/man2/sched_setaffinity.2.html
On Fri, Dec 16, 2016 at 2:09 PM, Steve Volumetric <volumetricsteve@gmail.com> wrote:
Hey everyone,
I'm about to set up a server (minecraft, sorry) and what I'd like to do is ensure consistency of service, even if it's at the cost of a performance hit.
My thinking is, if I can get crux to boot up...some way, maybe it could launch and lock all things brought up at system-startup-time to say...core 0. As far as many services would be concerned, they'd be on a single core system.
With my other 5 cores, I'd like to designate each core to a particular world, and this is done fairly easily, but my real question is up above.
Can I get crux to relegate its services to a single core consistently? If not one, maybe two?
Thanks
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